(Note: relabel angle Q as angle C and define the segment we have constructed opposite angle Q to be side c, and proceed from there). Angle Between Two Lines Let y = m1x + c1 and y = m2x + c2 be the equations of two lines in a plane where, m 1 = slope of line 1 c 1 = y-intercept made by line 1 m2 = slope of line 2 c2 = y-intercept made by line 2 (1) y=x 2-4x+4 --> (2) Let us learn how to find angle of intersection between these curves using this equation.. By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. Find the Angle by substituting slope values in Formula tan (θ) = (m1-m2)/ (1+ (m1.m2)) ∀ m1>m2 From formula θ = tan -1 [ (m1-m2)/ (1+ (m1.m2))] θ = tan -1 ((3.2+2.4)/ (1+ (3.2*-2.4)) θ = tan -1 (5.6/-6.68) θ = tan -1 (0.8383) θ = 39.974 ° Therefore, the angle of intersection between the given curve is θ = 39.974 ° You get cosine of that angle with: You can use formula for dot product: $$ u \dot v = \|u\| \|v\| \cos{\theta} $$ where $\theta$ is angle between vectors $u$ and $v$. Angle between two vectors - formula. Versions similar to the law of cosines for the Euclidean plane also hold on a unit sphere and in a hyperbolic plane. While Heading is an angle or direction where you are currently navigating in. The first is, where sinh and cosh are the hyperbolic sine and cosine, and the second is. Hint: Let $A = (x_1, y_1)$, and $B = (x_2, y_2)$, and $C = (x_3, y_3)$. 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